now, now 10.1 – Find the FCRIT for the given information: a. α=.05 DFB = 3 DFW = 17 FCRIT = __________ b. α=.01 DFB = 7 DFW =

now, now 10.1 – Find the FCRIT for the given information:

a. α=.05 DFB = 3 DFW = 17 FCRIT = __________

b.

α=.01

DFB = 7

DFW = 10

FCRIT = __________

c.

α=.01

DFB = 20

DFW = 25

FCRIT = __________

d.

α=.05

DFB = 5

DFW = 8

FCRIT = __________

e.

α=.05

DFB = 6

DFW = 23

FCRIT = __________

f.

α=.01

DFB = 9

DFW = 42*

FCRIT = __________

* Use the same “round down” rules you did with t tables!

10.2 – Using the information below, test the significance of the data:

A company has three manufacturing plants, and company leaders want to determine whether there is

a significant difference (use α = .01) in the average age of workers at the three locations. The

following data is the average age of five randomly selected workers at each plant. The data and the

partial results of a one-way ANOVA table are listed below:

Employees’ Ages (in Years)

Plant 1 Plant 2 Plant 3
29 32 25
27 33 24
30 31 24
27 34 25
28 30 26

n1 = 5 n2 = 5 n3 = 5

x1 = 28.2 x2 = 32.0 x3 = 24.8

Source of Variance df SS MS F

Between ? 129.73 64.87 ?

Within ? 19.60 1.63

Total 14 149.33

1. In the table, what is dfB?

2. In the table, what is dfW?

3. In the table, what is FOBS?

4. At α=.01, what is your FCRIT?

5. What is your research decision – accept H0 or reject H0?

N = 15 X = 28.33

10.3 – Using the information below, test the significance of the data:

A manager is concerned that one of his assembly lines is producing significantly more defective parts

than the other two assembly lines. He records the number of defective parts made by the three

assembly lines each day over the course of a week. The data and the partial results of a one-way

ANOVA table are listed below:

Number of Defective Parts Produced Each Day

Line 1 Line 2 Line 3
Mon 3 2 1
Tue 2 2 2
Wed 2 1 1
Thu 4 0 1
Fri 2 1 2

n1 = 5 n2 = 5 n3 = 5
x1 = 2.6 x2 = 1.2 x3 = 1.4

Source of Variance df SS MS F

Between ? 5.73 2.87 ?

Within ? 7.20 0.60

Total 14 12.93

1. In the table, what is dfB?

2. In the table, what is dfW?

3. In the table, what is FOBS?

4. At α=.05, what is your FCRIT?

5. What is your research decision – accept H0 or reject H0?

N = 15 X = 1.73

10.4 – Using the information below, test the significance of the data:

A group of paramedics does not believe that the number of emergency calls is the same for each shift.

To test their claim, they record the number of calls received during each shift for seven days. Based

on this data, can the paramedics conclude that the average number of calls is different between

shifts? The data and the partial results of a one-way ANOVA table are listed below:

Number of Emergency Calls Received per Shift

Morning Afternoon Night
Sun 2 3 5
Mon 3 4 4
Tue 2 4 5
Wed 4 5 3
Thu 3 3 2
Fri 1 2 5
Sat 3 5 6

n1 = 7 n2 = 7 n3 = 7
x1 = 2.6 x2 = 3.7 x3 = 4.3

Source of Variance df SS MS F

Between ? 10.67 5.33 ?

Within ? 24.57 1.37

Total 20 35.24

1. In the table, what is dfB?

2. In the table, what is dfW?

3. In the table, what is FOBS?

4. At α=.01, what is your FCRIT?

5. What is your research decision – accept H0 or reject H0?

N = 21 X = 3.52

10.5 – Using the information below, test the significance of the data:

A university is comparing the GPAs between the four sororities on campus. The GPAs for ten girls in

each sorority are shown below. Based on this data, can you conclude that there is a significant

difference in the average GPA between the four sororities on campus?

GPAs of Four Campus Sororities

Tri-Delta Phi Mu Chi Omega Beta Phi
2.5 3.1 2.7 3.1
3.4 3.4 2.9 3.2
4.0 3.6 2.8 3.1
3.8 3.6 2.8 2.8
2.7 3.7 2.9 2.9
2.8 3.0 3.1 3.1
2.8 4.0 2.9 3.0
3.2 3.9 2.7 3.3
3.1 4.0 2.6 2.7
3.9 3.4 3.3 2.6

n1 = 10 n2 = 10 n3 = 10 n4 = 10

x1 = 3.2 x2 = 3.6 x3 = 2.9 x4 = 3.0

Source of Variance df SS MS F

Between ? 2.88 0.96 ?

Within ? 4.53 0.13

Total 39 7.42

1. In the table, what is dfB?

2. In the table, what is dfW?

3. In the table, what is FOBS?

4. At α=.05, what is your FCRIT?

5. What is your research decision – accept H0 or reject H0?

N = 40 X = 3.16